Question

find the acceleration of the body moving on an inclined track of distance 200M in 45 sec​

Answer 1

Answer:

Given that,

The acceleration a=8m/s2

Initial velocity u=0m/s

We know that,

The displacement in the nth second

=u+a(n−21)

Now, the displacement in 5th second

  =0+8(5−21)

 =36m

Hence, the distance covered by it in fifth second is 36 m

Explanation:

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