Question

find the acceleration produce in a scooter starting from rest.
increases its speed to 8m/s. and covers
a
distance of
800m​

Answer 1

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

Initial velocity = zero

Final velocity = 8m/s

Distance travelled = 800m

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to find acceleration of scooter.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

➠ We can easily solve this question by applying third equation of kinematics.

• $\boxed{\bf{\blue{v^2-u^2=2as}}}$

where,

v ➝ final velocity

u ➝ initial velocity

a ➝ acceleration

s ➝ distance

$:\implies\tt\:v^2-u^2=2as$

$:\implies\tt\:8^2-0^2=2a(800)$

$:\implies\tt\:64=1600a$

$:\implies\underline{\boxed{\bf{\purple{a=0.04\:ms^{-2}}}}}$

Answer 2

Explanation:

Given -

Initial velocity (U) = 0m/s

Final Velocity (V)= 8m/s

Distance covered (S) = 800m

According to first law of motion:-

2AS = V^2 - U^2

so -

64-0 = 2x a x 800

a = 0.25 m/s^2