Question

TRIGONOMETRY A wheel of a motor is rotating at 1200 r.p.m. If the radius of the wheel is 35 cm, what
linear distance does a point of its rim traverse in 30 seconds?​

Answer 1

Answer:

1.32km

Step-by-step explanation:

In 30sec the rim will perform 600 rotations(1200/2)

Radius = 35cm = 0.35m

Circumference= 2 π r = 2 x 22/7 x 0.35 = 2.2

linear distance covered = circumference×no. of rotations = 2.2×600= 1320m =1.32km