Question

find the aera of triangle whose sides are 42 cm, 34cm,20cm, Also, Find the height corresponding to longest side

Answer 1

Let
a = 42 cm
b = 34 cm
c = 20 cm
So , s = ( a+b+c)/2 = (42+34+20)/2 cm = 48 cm
So , Area = √s(s-a)(s-b)(s-c) = √48(48-42)(48-34)(48-20) = √48*6*14*24 = 311.07 sq. cm
So , Corresponding to the longest side = Area*2/Longest side = 622.14/42 = 14.81 cm = 14.8 cm .......
HOPE IT HELPS.....
PLEASE MARK IT AS BRAINLIEST .........................

Answer 2

Hey There!

$= ( \frac{42 + 34 + 20}{2} )cm$

$= \frac{96}{2} \: cm$

Now,

$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ where \: (s) \: is \: the \: semi \: perimeter \: of \: the \: triangle.$

$\sqrt{48(48 - 42)(48 - 34)(48 - 20)}$

$\sqrt{48 \times 6 \times 14 \times 28}$
$\sqrt{112896}$

$= 336 cm²$