Question

find the algebraic expression.find two consecutive odd integers whose sum is 228.
​

Answer 1

$let \: one \: consecative \: number \: be \: x \\ and \: other \: will \: be(x + 2) \\ x + x + 2 = 228 \\ 2x = 226 \\ is \: equaction \: in \: one \: variable$

$let \: one \: number \: be \: x \: \\ other \: be \: y \\ according \: to \: te \: question \: \\ x + y = 228 \\ it \: is \: the \: equation \: in \: two \: variable$

hope this will help you

Answer 2

Answer:

Let the consecutive odd integers be x and x + 2

Sum = 228

⇒ x + x + 2 = 228

⇒ 2x + 2 = 228

⇒ 2x = 228 - 2

⇒ 2x = 226

⇒ x = 226/2 = 113

⇒ x + 2 = 113 + 2 = 115

Hence the two numbers are 113 and 115.

Algebraic Expression: 2x + 2 = 228