find the algebraic expression. the total cost of 4 chairs and 2 tables is ₹650. if a table costs ₹25 more than a chair, find the price of each.
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let the cost of chair be x and cist of table be (x+25)
ATQ
4*x+2*(x+25)=650
4x+2x+50=650
6x+50=650
6x =650-50
6x=600
x=600/6
x=100
cost of chair =100 rupees
cost of table =100+25
= 125 rupees
ATQ
4*x+2*(x+25)=650
4x+2x+50=650
6x+50=650
6x =650-50
6x=600
x=600/6
x=100
cost of chair =100 rupees
cost of table =100+25
= 125 rupees
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