find the all trigonometric ratios
Attachments:
Answers
Answered by
41
if tan theta is = 2mn / (m^2 - n^2)
sin theta / cos theta = 2mn / (m^2-n^2)
on comparing these equations
sin theta = 2mn
cos theta = (m^2 - n^2 )
cosec theta = 1 / sin theta
= 1 / 2mn
sec theta = 1 / cos theta
= 1 / (m^2 - n^2)
cot theta = 1 / tan theta
= 1/ (2mn / (m^2 - n^2)
= (m^2 - n^2) / 2mn
HOPE IT HELPS .
sin theta / cos theta = 2mn / (m^2-n^2)
on comparing these equations
sin theta = 2mn
cos theta = (m^2 - n^2 )
cosec theta = 1 / sin theta
= 1 / 2mn
sec theta = 1 / cos theta
= 1 / (m^2 - n^2)
cot theta = 1 / tan theta
= 1/ (2mn / (m^2 - n^2)
= (m^2 - n^2) / 2mn
HOPE IT HELPS .
venky2020:
you did well find the value of Hypotenuse
why there is need of finding hypotenuse
to know other values we need to find hypotenuse
hi
hi
Answered by
26
here is ur answer.....
Attachments:
your brilliant
did you seen my new question i hope the first answer given by you with in few minutes
hi
Similar questions