Question

Find the altitude and area of an isosceles triangle whose perimeter is 64 cm and whose base is 24 cm.

Answer 1

Answer:

area= 240cm square

Step-by-step explanation:

altitude of the triangle let be 'h' cm

perimeter of the triangle= 64cm

base of the triangle = 24cm

ATQ, 24 + h + h = 64

=> 2h= 64-24 = 40

=> h= 40/2 20cm

height= 20cm

area = 1/2 x b x h

= 1/2 x 24 x 20

= 24 x 10

= 240cm square