Question

find the altitude and area of an isosceles triangle whose perimeter is 64 cm​

Answer 1

Step-by-step explanation:

let the equal sides be x and x

perimeter of a triangle = sum of all sides

64 = x + x+ 24

64 = 2x +24

64-24 =2x

40 =2x

40÷2 = x

20 = x

the sides are 20cm , 20cm ,24 cm

by heron's formula,

semi perimeter = perimeter ÷2

s =64÷2

=32 cm

area of triangle = sq rt / s ( s-a) ( s-b) (s-c)

= sq rt / 32 ( 32 - 24 ) ( 32 - 20 ) (32- 20)

= sq rt / 2 ×2×2×2 ( 8 ) ( 12 ) ( 12 )

= 4 sq rt / 2×2 ×2×2 ×2×2 × 3×3 ×2

= 4×8×3 sq rt / 2

= 32×3 sq rt / 2

= 96 sq rt / 2 cm²

area of triangle = 1/2 × base × height

96 sq rt /2 = 1/2 × 24 × hieght

2( 96 sq rt /2 ) = 24 × hieght

192 sq rt / 2 = 24 × hieght

192 sq rt /2 ÷ 24 = hieght

8 sq rt / 2 = hieght

11.31 cm = hieght

Answer 2

Answer:

Deoxyribonucleic Acid

Step-by-step explanation:

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