Question

Find the altitude and area or an isosceles triangle whose perimeter is 64cm and whose base is 24cm​

Answer 1

Answer:

Altitude  isosceles triangle is 16 cm

Area of the triangle is  196 $cm^2$

Step-by-step explanation:

Let other two  side be x

Perimeter of the isosceles triangle is

$64 cm = x+x+24\\ 2x=64-24\\2x=40\\x=20$

We can consider right angles triangle with base as 12 cm and hypotenuses as 20 cm , opposite side is taken as altitude= y of the isosceles triangle.

$20^2=y^2+(24/2)^2\\y^2=20^2-12^2\\y^2=400-144\\y=\sqrt{256} \\y=16 cm$

Altitude  is 16 cm

Area of the triangle is

$A=\frac{1}{2} b h\\ A=\frac{1}{2}\times 24 \times 16\\A=192 cm^2$

Area of the triangle is  196 $cm^2$