Question

Find the altitude of a parallelogram whose area is 2.25 m sq. and the base is 250 cm.

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Answer 1

Given:-

• Area of the parallelogram is 2.25 m².
• Base of the parallelogram is 250 cm.

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To find:-

• Altitude of the parallelogram.

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Solution:-

• Base = 250 = 2.5 m

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☆Area of parallelogram = base × height

→ 2.25 = 2.5 × h

→ h = 2.25/2.5

→ h = 0.9 m

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Hence,

• the altitude of the parallelogram is 0.9 m.

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\; Square\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$

Answer 2

Area =

bh [In gm]

Given Area

$= 2.25m,b=2.5m$

$h = bArea = 2.5(2.25)$

$= 250225=0.9m$

$Altitude = 90cm$