Find the equation that formed by each root of x2 – x – 1 = 0 is multiplied by 3.
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Answered by
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hghvgh cfhxh
Explanation:
let p,q be roots of equation ax
2
+bx+c=0
So p+q=(−
a
b
) and pq=c/a
⇒b=−a(p+q),c=apq
New equation is x
2
+36x+24=0 and roots are 2p,2q
So 2p+2q=−36
⇒p+q=−18
2p×2q=24
⇒pq=6
Then, value of bc is [−a(p+q)][apq]=−a(−18)a6=108a
2
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