find the altitude of a triangle whise base is 3 dm and area is 18 m sq
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Base,b=3 dm=0.3 m
Area = 1/2bh
18=1/2×0.3×h
h= 18×2/0.3
= 18×2×10/3
=120 m
h is the altitude
Area = 1/2bh
18=1/2×0.3×h
h= 18×2/0.3
= 18×2×10/3
=120 m
h is the altitude
Answered by
2
base =3dm=0.3m
area=18m
we know that area=1/2 bh
18=1/2*0.3*h
h=(18*2)/0.3
h=120m
area=18m
we know that area=1/2 bh
18=1/2*0.3*h
h=(18*2)/0.3
h=120m
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