Find the altitude of a triangle whose area is 120m^ with base 10m
Answers
Answered by
1
Answer:
Step-by-step explanation:
Area of triangle=1/2×altitude× base
120msq=1/2×altitude×10m
120×2=altitude×10
240÷10=altitude
24m=altitude
Answered by
1
Answer:
hb=24m
b Base
10
m
A Area
120
m²
Using the formula
A=hbb
2
Solving forhb
hb=2A
b=2·120
10=24m
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