find the altitude of an equilateral triangle of side 4cm
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Secondary School Math 5 points
The altitude of an equilateral triangle is 4 cm, then
the area of triangle is:
Ask for details Follow Report by Pari1398 27.07.2019
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suhani678
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Step-by-step explanation:
Let ABC be a right angled triangle,
and AD be the altitude.
we know that altitude of equilateral triangle is bisector.
so, BD= CD
AND, AB= 1/2 BD
by pythagoras theorm,
AD^2= AB^2 + BD^2
4^2 = AB^2 + ( 1/2AB)^2
16 = AB^2 +1/4AB^2
16= 5/4AB^2
AB^2 = (16×4)/5
AB^2 = 64/5
AB= 8/√5 cm
AREA = 1/2×BASE×HEIGHT
area = 1/2× 8/√5× 4
area= 16/√5 cm^2
Answer:
AREA OF EQUILATERAL TRIANGLE IS ROOT3/4 ASQUARE
ROOT3/4 (4)(4)=ROOT3(4)
1/2 (BASE)(HEIGHT)=AREA OF TRIANGLE
1/2 (4)(H)=ROOT3(4)
H =2ROOT3
Step-by-step explanation: