Question

Find the altitude of triangle with three sides 17cm 8cm and 15cm corresponding to longest
side​
urgent h please help

Answer 1

Answer:

Altitude = 7.05 cm

Step-by-step explanation:

Area of the triangle = $\sqrt{S (S-a)(S-b)(S-c)}$

a = 17 cm

b = 15 cm

c = 8 cm

therefore, S = perimeter/2 = (17+15+8)/2

= 40/2 = 20 cm

Thus, Area = $\sqrt{20(20-17)(20-15)(20-8)} \\\sqrt{20*3*5*12} \\\sqrt{4*5*3*5*4*3}$

= 4*3*5 = 60 sq.cm

Area is also = 1/2*Base*height

here, base = a = 17 cm

Thus, height = area*2/base = 60*2/17

= 120/17 = 7.05 cm

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