Question

Find the amount and C.I. when p=6000 Rs. R=5% and

time 2 year.​

Answer 1

Answer:

Compound interest: RS 1260

Step-by-step explanation:

Here is what we have:

Principal (p) = RS 6000

Time (t) = 2 years

Rate (r) = 10%

$Amount (A) = p(1+r)^t \:$

$= </p><p>6000(1+0.10)^2 \:$

$= </p><p>6000(1.1)^2 \: \\ </p><p>= </p><p>6000*1.21 \\ </p><p>= </p><p>7260$

$Compound Interest (C.I)=A-P \\ </p><p>= </p><p>Rs (7260-6000) \\ </p><p>= </p><p>Rs 1260$

So your answer would be: Rs 1260

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Answer 2

Given that, P = 6000, R = 5%, T = 2 yrs

we can write that:

Amount = P(1 + (R/100))^T

=> 6000(1 + (5/100))^2

=> 6000(1 + (1/20))^2

=> 6000 x (21/20)^2

=> 6000 x (21/20) x (21/20)

=> 300 x (21/20) x 21

=> 15 x 21 x 21

=> 15 x 441

=> 6615

Therefore the compounded amount is 6615

The compound interest has the same formula as the simple interest, since they both are interests.

CI = (PRT)/100

CI = (6000 x 5 x 2)/100

CI = 60000/100

CI = 600

Therefore, the compound interest is 600

I HOPE IT HELPS :)