Question

find the amount and compound interest if P = 4000, R = 7.5, N=2 yrs​

Answer 1

Answer:

solved

Step-by-step explanation:

amount = p( 1+r)^n = 4000(1.075)² = 4622.5

compound interest =  p( 1+r)^n - p = 622.5

Answer 2

Here, P = ₹ 4000; R = 7.5 % ; N = 2 years

A=P(1+R100)N =4000(1+7.5100)2 =4000(1+751000)2 =4000(10751000)2 =4000(4340)2 =4622.50 Rupees∴ Compound Interest after 2 years,I = Amount − Principal =4622.50−4000 =622.50 Rupees

Hence, Amount = ₹ 4622.50 and Compound interest = ₹ 622.50