Question

Find the amount and compound
interest on 10000 for 2 years at 11%
per annum
annum compounded annually.​

Answer 1

Answer:

A=P(1+R/100)^N

A= 10000(1+11/100)^2

A=10000(111/100)^2

A=10000(111/100×111/100)

A=10000(12321/10000)

A=10000×12321/10000

A=12321

THEREFORE, CI= A-P

=12321-10000

=2321

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Answer 2

Given,
Principal=Rs. 10000
Rate =11%
Time =2 years

Compound=P(1+
100
r
​
)
2

=10000(1+
100
11
​
)
2

=10000×
10000
(111)
2

​

=12321

Amount=12321−10000=2321.
.
.
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