Find the amount and compound
interest on 10000 for 2 years at 11%
per annum
annum compounded annually.
Answers
Answered by
5
Answer:
A=P(1+R/100)^N
A= 10000(1+11/100)^2
A=10000(111/100)^2
A=10000(111/100×111/100)
A=10000(12321/10000)
A=10000×12321/10000
A=12321
THEREFORE, CI= A-P
=12321-10000
=2321
hope it helps
plz mark my answer as the brainliest
thanks
Answered by
3
Given,
Principal=Rs. 10000
Rate =11%
Time =2 years
Compound=P(1+
100
r
)
2
=10000(1+
100
11
)
2
=10000×
10000
(111)
2
=12321
Amount=12321−10000=2321.
.
.
plz mark me brainliest
Principal=Rs. 10000
Rate =11%
Time =2 years
Compound=P(1+
100
r
)
2
=10000(1+
100
11
)
2
=10000×
10000
(111)
2
=12321
Amount=12321−10000=2321.
.
.
plz mark me brainliest
Similar questions