Question

find the amount and compound interest on 16000 for 3 years at 5% per annum counted annually

Answer 1

Amount = p(1+r/100)^n
             = 16000(1+5/100)³
             = 16000(1+1/20)³
              = 16000( 9261/8000)
              = 18522 Rs
C.I = amount - principle
      = 18522 - 16000 = 2522 Rs

Answer 2

Hello............ ^_^

Here is your answer....

Given:-
Principal (P) = Rs. 16000
Rate of interest = 5% per annum
Time (n) = 3 years

$Amount = P {(1 + \frac{R}{100} )}^{n} \\ \\ = 16000 {(1 + \frac{5}{100} )}^{3} \\ \\ = 16000 {(1 + \frac{1}{20} )}^{3} \\ \\ = 16000 {( \frac{20 + 1}{20} )}^{3} \\ \\ = 16000 {( \frac{21}{20} )}^{3} \\ \\ = 16000 \times \frac{21 \times 21 \times 21}{20 \times 20 \times 20} \\ \\ = 16000 \times \frac{9260}{8000} \\ \\ (16000 \div 8000 = 2) \\ \\ = 2 \times 9260 \\ \\ = 18522$
Amount = Rs. 18522

C.I = Amount - Principal
C.I = 18522 - 16000 = 2522
C.I = Rs. 2522




Hope it helps.............. ^_^