Question

Find the amount and compound interest on ₹16000 for112year at 6% per annum compounded annually.

Answer 1

Answer:

this is the answer for ur que

Answer 2

Given :-

• P = Rs.16000 .
• T = 1(1/2) years .
• R = 6% per annum .

To Find :-

• A and CI = ?

Solution :-

we know that, when time is in fraction and rate is compounded annually,

• Let Time whole = W .
• Fraction Time = F .

Then, Amount will be :-

• Amount = P[1 + (R/100)]^(W) * [ 1 + {(F * R)/100}]

Putting Values we get,

→ A = 16000 * [1 + (6/100)]¹ * [1 + {(1/2 * 6)/100}]

→ A = 16000 * [1 + (3/50] * [1 + (3/100)]

→ A = 16000 * (53/50) * (103/100)

→ A = (16 * 53 * 103)/5

→ A = Rs.17468.8 (Ans.)

therefore,

→ CI = A - P

→ CI = 17468.8 - 16000

→ CI = Rs.1468.8 (Ans.)

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