find the amount and compound interest on ₹
3000 at 2 year 10% per annum
Answers
Answer:
Given,
\begin{gathered} \bf{Principal} = \rm 3000 \\ < /p > < p > \bf{}Time = \rm 2 \: \: yrs\\ < /p > < p > \bf{}Rate = \rm10\% \: \: \: per \: annum\end{gathered}
Principal=3000
</p><p>Time=2yrs
</p><p>Rate=10%perannum
\begin{gathered} \huge\text{Formula Used :- } \\ \\ \bull \: \: \tt Amount = { \tt P \bigg(1 + \frac{R}{100} \bigg)^{t} }\\ \\ \bull \: \: \tt Compund \: Interest = { \tt P \bigg(1 + \frac{R}{100} \bigg)^{t} - P} \\ \\ \end{gathered}
Formula Used :-
∙Amount=P(1+
100
R
)
t
∙CompundInterest=P(1+
100
R
)
t
−P
So,
\begin{gathered} \rm{}Amount = 3000 { \bigg(1 + \frac{1\cancel0}{10\cancel0} \bigg)}^{2} \\ \\ = > 3000 {\bigg(1 + \frac{ 1 }{10} \bigg)}^{2} \\ \\ = > 3000 \times {\bigg( \frac{10 + 1}{10} \bigg)}^{2} \\ \\ = > 3000 \times \frac{ {11}^{2} }{ {10}^{2} } \\ \\ = > 30\cancel{00 }\times \frac{121}{1\cancel{00}} \\ = > 30 \times 121 \\\implies \red{ 3630}\end{gathered}
Amount=3000(1+
10
0
1
0
)
2
=>3000(1+
10
1
)
2
=>3000×(
10
10+1
)
2
=>3000×
10
2
11
2
=>30
00
×
1
00
121
=>30×121
⟹3630
And,
\begin{gathered} \rm{}CI = A - P \\ \\ = > 3630 - 3000 \\ = > \red{630}\end{gathered}
CI=A−P
=>3630−3000
=>630
Hence,
Amount = Rs. 3630
Interest = Rs. 630
Answer:
Answer :
Rs 3630, Rs 630
find the amount and compound interest on ₹
3000 at 2 year 10% per annum