find the amount and compound interest on 5000 rupees for 2 years at 10%, interest being payable yearly
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Solution. Here, P= Rs 5000, R = 10%, n = 2 years
Using the formula, A (Amount) = P (1+R100)n, we have
Therefore, A = Rs 5000 (1+10100)2
= Rs 5000 x 110100 x 110100
= Rs 6050
Therefore, Compound Interest = A – P = Rs 6050 – Rs 5000 = Rs 1050.
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Using the formula, A (Amount) = P (1+R100)n, we have
Therefore, A = Rs 5000 (1+10100)2
= Rs 5000 x 110100 x 110100
= Rs 6050
Therefore, Compound Interest = A – P = Rs 6050 – Rs 5000 = Rs 1050.
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