find the amount and compound interest on rupees 15000 for year 3 at 4% annual rate of interest
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Step-by-step explanation:
For SI,
P = ₹15000
T = 3 yrs
R = 4%p.a.
SI = PxRxT/100
= 15000 x 3 x 4 / 100
= 150 x 3 x 4
= ₹1800
For CI,
P = ₹15000
T = 3yrs
R = 4%p.a
A = P ( 1 + R/100 ) T
A = 15000 ( 1 + 4/100 ) 3
A = 15000 ( 104/100 ) 3
A = 15000 x 104/100 x 104/100 x 104/100
A = 15000 x 26/25 x 26/25 x 26/25
A = ₹16872.96
CI = A - P
= ₹16872.96 - ₹15000
= ₹1872.96
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