Question

find the amount and compound interest when principal is equals to Rupees =6000 ,time = 2 years and rate = 10% per annum​

Answer 1

Answer:

Compound interest: RS 1260

Step-by-step explanation:

Here is what we have:

Principal (p) = RS 6000

Time (t) = 2 years

Rate (r) = 10%

$Amount (A) = p(1+r)^t$

= $6000(1+0.10)^2$

= $6000(1.1)^2$

= $6000*1.21$

= $7260$

$Compound Interest (C.I)=A-P$

= $Rs (7260-6000)$

= $Rs 1260$

So your answer would be: Rs 1260

MARK brainiest if this was helpful.

Answer 2

Answer:

Compound interest = 1,260 Rs

Step-by-step explanation:

Given that-

Principal = 6,000 Rs

Time = 2 years

Rate = 10% per year

Compound year =?

We know that-

$A = P[1+\dfrac{r}{100}]^{n}$

Where A = Addition amount

P = Principal amount

r = rate

n = time

$A = 6000[1+\dfrac{10}{100}]^{2}$

$A = 6000[1+0.1]^{2}$

$A = 6000(1.21)^{2}$

$A = 6000 \times 1.21$

A = 7,260 Rs

Addition amount = 7,260 Rs

Compound interest = Addition amount - principal amount

                                 = 7260 - 6000

Compound interest = 1,260 Rs