Question

Find the amount and compound interest when the interest is compounded
annually.

i) Principal = Rs 5000, Time = 3 years,Rate = 5% per annum

ii) Principal = Rs 2000,Time = 2 years,Rate = 8% per annum


Answer plz​

Answer 1

Answer:

hope my answer will help u

Step-by-step explanation:

1

st

year

Principal, P=Rs.5000

Time, T=1 year

Rate of interest ,R=6%

∴simple Interest, SI=

100

PTR

=

100

5000×10×6

=Rs.300

∴Amount=P+SI=Rs.5300

2nd year

Principal = Amount of 1st year=Rs.5300

Rate of interest =8%

Time =1 year

∴ Interest =

100

5300×1×8

=Rs.424

∴ Amount =Rs.(5300+424)=Rs.5724

The interest of 2nd year is the required compound interest. So, C.I=rs.424 and the required amount is Rs.5724

Answer 2

Formulas used in this question :

$\boxed{ \sf \purple{Amount = \green{P \: \bigg[1 \: + \: \dfrac{R}{100} \bigg]^{n} }}}$

$\boxed { \sf \purple {Compound \: interest \: = \green{ \: Amount \: - \: Principal }} }$

Solution : 1

$\bf \red{Given \: : }$ ↴

$\sf \: Principal \: : \: Rs. 5000$

$\sf \: Time \: : \: 3 \: years$

$\sf \: Rate \: : \: 5 \: \%$

$\bf \: \red{To \: find \: : }$ ↴

$\sf We \: have \:to \:find \:the \:amount\: and \:CI.$

$\bf \red{So, \: Let's \: Start : }$ ↴

$\sf Amount = 5000 \: \bigg[1 \: + \: \dfrac{5}{100} \bigg]^{3}$

$\sf Amount = 5000 \: \bigg[1 \: + \: \dfrac{1}{20} \bigg]^{3}$

$\sf Amount = 5000 \: \bigg[ \dfrac{20 + 1}{20} \bigg]^{3}$

$\sf Amount = 5000 \: \times \: \dfrac{21}{20} ^{3}$

$\sf Amount = 5000 \: \times \: \dfrac{9261}{8000}$

$\sf Amount = 5 \: \times \: \dfrac{9261}{8}$

$\sf Amount = \dfrac{46305}{8} \: = \red{Rs. \: 5788.125}$

$\sf \: CI = \: 5788.125 \: - \: 5000 \: = \: \red{Rs. \: 788.125 }$

________________________________

Solution - 2

$\bf \red{Given \: : }$ ↴

$\sf \: Principal \: : \: Rs. 2000$

$\sf \: Time \: : \: 2\: years$

$\sf \: Rate \: : \: 8 \: \%$

$\bf \: \red{To \: find \: : }$ ↴

$\sf We \: have \:to \:find \:the \:amount\: and \:CI.$

$\bf \red{So, \: Let's \: Start : }$ ↴

$\sf Amount = 2000 \: \bigg[1 \: + \: \dfrac{8}{100} \bigg]^{2}$

$\sf Amount = 2000 \: \bigg[1 \: + \: \dfrac{2}{25} \bigg]^{2}$

$\sf Amount = 2000 \: \bigg[ \: \dfrac{25 + 2}{25} \bigg]^{2}$

$\sf Amount = 2000 \: \times \: \dfrac{27}{25} ^{2}$

$\sf Amount = 2000 \: \times \: \dfrac{729}{625}$

$\sf \: So, \: the \: amount \: = \red{ Rs. \: 2332.8 }$

$\sf \: CI = \: 2332.8 \: - \: 2000 \: = \: \red{Rs. \: 332.8 }$