Find the amount and compound intrest on Rs625000 for 1 year at the rate of 8% p.a compounded half yearly
Answers
Solution :
- Principal, (P) = Rs.625000
- Rate, (R) = 8% p.a.
- Time, (n) = 1 year
Using formula of the compounded half-yearly;
A/q
Now, as we know that compound Interest;
⇒ C.I. = Amount - Principal
⇒ C.I. = Rs.676000 - Rs.625000
⇒ C.I. = Rs.51000
Thus;
The amount & compound Interest will be Rs.676000 & Rs.51000 .
Answer:
Solution :
Given:
Principal, (P) = Rs.625000
Rate, (R) = 8% p.a.
Time, (n) = 1 year
Explanation:
Using formula of the compounded half-yearly;
{Amount=Principal(1+frac{R}{2\times 100}{2n}
Amount=Principal(1+
2×100
R
)
2n
A/q
\begin{gathered}\mapsto\sf{A=625000\bigg(1+\dfrac{\cancel{8} }{\cancel{2} \times 100} \bigg)^{(2\times 1)}}\\\\\\\mapsto\sf{A=625000\bigg(1+\cancel{\dfrac{4}{100}} \bigg)^{2}}\\\\\\\mapsto\sf{A=625000\bigg(1+\dfrac{1}{25} \bigg)^{2}}\\\\\\\mapsto\sf{A=625000\bigg(\dfrac{25+1}{25} \bigg)^{2}}\\\\\\\mapsto\sf{A=625000\bigg(\dfrac{26}{25} \bigg)^{2}}\\\\\\\mapsto\sf{A=\cancel{625000} \times \dfrac{26}{\cancel{25}}\times \dfrac{26}{\cancel{25}} }\\\\\\\mapsto\sf{A=Rs.(1000 \times 26\times 26)}\\\\\end{gathered}
↦A=625000(1+
2
×100
8
)
(2×1)
↦A=625000(1+
100
4
)
2
↦A=625000(1+
25
1
)
2
↦A=625000(
25
25+1
)
2
↦A=625000(
25
26
)
2
↦A=
625000
×
25
26
×
25
26
↦A=Rs.(1000×26×26)
\mapsto\bf{A=Rs.676000}↦A=Rs.676000
Now, as we know that compound Interest;
⇒ C.I. = Amount - Principal
⇒ C.I. = Rs.676000 - Rs.625000
⇒ C.I. = Rs.51000
Thus;
The amount & compound Interest will be Rs.676000 & Rs.51000 .