Question

Find the amount and the CI of Rs. 64000 for 3 years at 12% pa.. compounded
annually​

Answer 1

Answer:

amount = 64000(1+12/100)³

= 64000 ×( 112 /100 )³

= 89915.39

ci = a - p

= 89915.39 - 64000

= 25915.39 rupees

hope it helps

Answer 2

Given:-

• Principal = Rs. 64000.
• Time period = 3 years.
• Rate of interest = 12%.

To find:-

• Amount
• Compound interest.

Solution:-

• For Amount :

We know that,

$\large \boxed{ \sf Amount = P{(1 + \dfrac{r}{100}) }^{n} }$

In which,

• P is principal.
• r is Rate of interest.
• n is time period.

P = Rs. 64000.

n = 3 years.

r = 12%.

Put all values,

$\implies \sf 64000 \times {(1 + \dfrac{12}{100} )}^{3}$

$\implies \sf 64000 \times {( \dfrac{100 + 12}{100} })^{3}$

$\implies \sf 64000 \times {( \dfrac{112}{100} )}^{3}$

$\implies \sf 640 \cancel{00} \times \dfrac{112}{1 \cancel{00}} \times \dfrac{112}{100} \times \dfrac{112}{100}$

$\implies \sf \dfrac{899153920}{10000}$

$\implies \sf 89915.392$

Amount = Rs. 89915.392

• For compound interest :

We also know that

$\large \boxed{ \sf Compound\: interest = Amount - Principal}$

So,

$\implies \sf 89915.392-64000$

$\implies \sf 25915.392$

Compound interest = Rs. 25915.392

Therefore,

Amount is Rs. 89915.392.

Compound interest is Rs. 25915.392