Math, asked by archanatriparhi422, 2 months ago

Find the amount and the compound interest on ₹ 10,000 for two years at 5% per annum

compounded yearly​

Answers

Answered by amitvicky30528
3

Answer:

interest on Rs 10,000 for 1

2

1

years at 10% per annum, compounded half yearly. Would this interest be more than the interest he would get if it was compounded annually?

Answered by BrainlyTopper97
84

{\large{\boxed{\underline{\mathrm{\bf{\orange{Given:-}}}}}}}

  • Sum of money (Principal) = ₹10,000
  • Rate of Interest = 5% p.a.
  • Time = 2 years

{\large{\boxed{\underline{\mathrm{\bf{\red{To \ Find:-}}}}}}}

  • Amount and Compound Interest

{\large{\boxed{\underline{\mathrm{\bf{\pink{Formula \ Used:-}}}}}}}

\bigstar \ {\boxed{\tt{\green{C.I. = P \ \bigg [ \bigg ( 1 + \dfrac{R}{100} \bigg ) ^n - 1 \bigg ] }}}} \ \bigstar

where,

  • C.I. = Compound Interest
  • P = Principal i.e. ₹10,000
  • R = Rate of Interest i.e. 5% p.a.
  • n = Time period i.e. 2 years

\bigstar \ {\boxed{\tt{\red{A = P + I}}}} \ \bigstar

where,

  • A = Amount
  • P = Principal
  • I = Interest

{\large{\boxed{\underline{\mathrm{\bf{\blue{Solution:-}}}}}}}

Let, the time be n.

Given :-

  • Sum of money (Principal) = ₹10,000
  • Rate of Interest = 5% p.a.
  • Time = 2 years

According to the question by using the formula of Compound Interest, we get,

\longmapsto {\mathsf{C.I. = Rs. \ 10,000 \ \bigg [ \bigg ( 1 + \dfrac{5}{100} \bigg ) ^2 - 1 \bigg ] }}

\longmapsto {\mathsf{C.I. = Rs. \ 10,000 \ \bigg [ \bigg ( \dfrac{100 + 5}{100} \bigg ) ^2 - 1 \bigg ] }}

\longmapsto {\mathsf{C.I. = Rs. \ 10,000 \ \bigg [ \bigg ( \dfrac{105}{100} \bigg ) ^2 - 1 \bigg ] }}

\longmapsto {\mathsf{C.I. = Rs. \ 10,000 \ \bigg [ \bigg ( \dfrac{21}{20} \times \dfrac{21}{20} \bigg ) - 1 \bigg ] }}

\longmapsto {\mathsf{C.I. = Rs. \ 10,000 \ \bigg [ \dfrac{441}{400} - 1 \bigg ] }}

\longmapsto {\mathsf{C.I. = Rs. \ 10,000 \ \bigg [ \dfrac{441 - 400}{400} \bigg ] }}

\longmapsto {\mathsf{C.I. = Rs. \ 10,000 \ \times \dfrac{41}{400}}}

\longmapsto {\mathsf{C.I. = Rs. \ \dfrac{4,10,000}{400}}}

\Longrightarrow {\mathsf{C.I. = Rs. \ 1025}}

{\orange{\bigstar}} \ \therefore {\boxed{\underline{\mathsf{\green{Compound \ Interest}{\red{ \ is \ }{\blue{\bf{Rs. \ 1025}}}}}}}} \ {\orange{\bigstar}}

According to the question by using the formula of Amount, we get,

: \longmapsto {\mathsf{Amount = Rs. \ (10,000 + 1025)}}

: \longmapsto {\mathsf{Amount = Rs. \ 11,025}}

{\orange{\bigstar}} \ \therefore {\boxed{\underline{\mathsf{\green{Amount}{\red{ \ is \ }{\blue{\bf{Rs. \ 11,025}}}}}}}} \ {\orange{\bigstar}}

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