Question

what is the temperature it which the kenetic energy of 0.3moles of helium is equal to the kenetic energy of 0.4moles of argan at 400k​

Answer 1

Given :

• Kinetic Energy of helium is equal to kinetic energy of argon
• Mole of helium (n1) = 0.3
• Mole of argan (n2) = 0.4
• Temperature of argon (T2) = 400K

To Find :

• Temperature of Helium (T1)

Formula Used :

$\bullet\underline{\boxed{\sf KE = \dfrac{3}{2}nRT}}$

n = mole

R = Gas Constant

T = Temperature

Solution :

$\implies{\sf KE_{He}=KE_{Ar}}$

$\implies{\sf \dfrac{3}{2}n_1RT_1=\dfrac{3}{2}n_2RT_2}$

$\implies{\sf n_1T_1=n_2T_2}$

$\implies{\sf 0.3 \times T_1=0.4 \times 400}$

$\implies{\sf T_1=\dfrac{0.4 \times 400}{0.3}}$

$\implies{\sf T_1=\dfrac{160}{0.3} }$

$\implies{\bf T_1=533.3K}$

Answer :

Temperature for helium is 533.3K