Question

निम्नलिखित व्यंजक को a + ib के रूप मे व्यक्त कीजिए : $\dfrac{(3 + \iota \sqrt 5)(3 - \iota \sqrt 5)}{(\sqrt 3 + \sqrt 2\,\iota) - (\sqrt 3 - \iota \sqrt 2)}$

Answer 1

sorry l don't understand maths in hindi

SORRY!!!!!!!!!

Answer 2

Answer:

Step-by-step explanation:

व्यंजक को a + ib के रूप मे व्यक्त  करना  -

प्रश्नानुसार  

$\dfrac{(3 + \iota \sqrt 5)(3 - \iota \sqrt 5)}{(\sqrt 3 + \sqrt 2\,\iota) - (\sqrt 3 - \iota \sqrt 2)}$

$\frac{(3)^{2}-(i\sqrt{5})^{2} }{\sqrt{3} +\sqrt{2}i-\sqrt{3} +\sqrt{2}i } \\\\=\frac{9-i^{2}*5}{2\sqrt{2}i } \\\\=\frac{9-(-1)5}{2\sqrt{2}i} \\\\=\frac{9+5}{{2\sqrt{2}i}} \\\\=\frac{14}{{2\sqrt{2}i}} \\\\=\frac{7}{\sqrt{2}i } *\frac{i}{i} =\frac{7i}{-\sqrt{2} } \\\\=-\frac{7}{\sqrt{2} }i\\ \\=\frac{-7\sqrt{2} }{2} i$