find the amount and the compound interest on 160000 for 2 year at 10%per annum compounded half yearly
Answers
Answered by
71
Answer:
Step-by-step explanation:
P=₹160000
R=10% per annum
=(10/2)% per half year
=5% per half year
T=2 years
=(2×2) half years
=4 half years
A=[P(1+R/2×100)^2T]
=₹[160000(1+5/100)^4]
=₹[160000{(100+5)/100}^4]
=₹[160000{105/100}^4] =₹[160000×(105/100)×(105/100)×(105
/100)×(105/100)]
=₹194481
CI=A - P
=₹(194481 - 160000)
=₹34481
Hope it helps...
Answered by
4
Answer:
Given Rate = 10% annum
= 5% per half year
time = 2 years = 4 half year
Amount =P(1+R/100 ) n
=160000(1+ 5/100 ) 4
= Rs. 194481
Compound Interest = Amount - Principal
= 194481 - 160000
= Rs. 34481
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