Math, asked by aliansar6542111, 1 month ago

Find the amount and the compound interest on 2000 at 10% p.a. for 2 years, compounded annually.​

Answers

Answered by 173tanveer
10

Answer:

Compound Interest =  Rs  538.1

Explaination:

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Attachments:
Answered by thebrainlykapil
65

Given :

  • Principal (P) = Rs 2000
  • Time (n) = 2 years
  • Rate (R) = 10% per annum

 \\

To Find :

  • Amount
  • Compound Interest

 \\

Formula :

\red \bigstar \: {\underline \orange {\boxed{\mathcal {\pmb{\color{blue}\quad Amount \: = \: Principal \: \times \bigg(\:1 \: + \: \dfrac{Rate}{100}\bigg)^{n} \quad}}}}}

\red \bigstar \: {\underline \orange {\boxed{\mathcal {\pmb{\color{blue}\quad Compound \: Interest \: = \: Amount \: - \: Principal \quad}}}}}

 \\

Solution :

{:} \longrightarrow \sf \: Amount \: = \: Principal \: \times \bigg(1 \: + \: \dfrac{Rate}{100}\bigg)^{n} \\ \\

{:} \longrightarrow \sf \: Amount \: = \: 2000 \: \times \bigg(1 \: + \: \dfrac{10}{100}\bigg)^{2} \\ \\

{:} \longrightarrow \sf \: Amount \: = \: 2000 \: \times \: \bigg(\dfrac{110}{100}\bigg)^{2} \\ \\

{:} \longrightarrow \sf \: Amount \: = \: 2000 \: \times \: \dfrac{110}{100} \: \times \: \dfrac{110}{100} \\ \\

{:} \longrightarrow \sf  \: Amount \: = \: 2 \cancel{000} \: \times \: \dfrac{110}{1 \cancel{00}} \: \times \: \dfrac{11 \cancel0}{1 \cancel{00}} \\ \\

{:} \longrightarrow \sf \: Amount \: = \: 2 \: \times \: 110  \:  \times  \: 11\\ \\

{:} \longrightarrow \sf \: Amount \: = \: 110  \:  \times  \: 22\\ \\

{:} \longrightarrow \underline  { \color{green} \boxed { \color{red} \bf \: Amount \: = \: Rs \: 2420 }} \color{navy} \: \: \bigstar \\

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{:} \longrightarrow \sf \: Compound \: Interest \: = \: Amount \: - \: Principal \\ \\

{:} \longrightarrow \sf \: Compound \: Interest \: = \: 2420 \: - \: 2000 \\ \\

{:} \longrightarrow \underline {\color{red}\boxed { \color{green} \bf \: Compound \: Interest \: = \: Rs \: 420 }} \color{pink} \: \: \bigstar \\

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\qquad \therefore\: \sf{ Amount \: = \underline {\underline{ Rs \: 2420}}}\\

\qquad \therefore\: \sf{ Compound \: Interest \: = \underline {\underline{ Rs \: 420}}}\\

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