Question

Find the amount and the compound interest on 3,20,000 for 2 years at 10% per annum
compounded half-yearly.

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Answer 1

Answer:

A=370440rs, c.i=50,440rs

Step-by-step explanation:

compounded half yearly means intrest will charge every 6 months.

so for 2 years it will be 4 half years..

so t=4 years, and r= 10/2=5%

for 1st year c.i= 5% of 320000=16000

for 2nd year c.i=5% of 336000=16800

for 3rd year c.i = 5% of 352800=17640

for 4th year c.i=5% of 370440=18522

total c.i for 4 years is 370440-320000=50,440rs

and amount is 370440

hope you understand

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Answer 2

Given:

$\huge\mathfrak\blue\star$ Principal(p)= Rs.320000

$\huge\mathfrak\red\star$ Rate (r)= 10% p.a= 5% Half Yearly

$\huge\mathfrak\orange\star$ Period(n)= 2 Years =4 half Years

To find:

Amount And Compound Interest

Solution:

$\color{green} \implies \tt \color{lime}{ \therefore \: Amount = P(1 + \frac{r}{100} ) {}^{n} } \\ \color{green} \: \rightarrow320000(1 + \frac{5}{100} ) {}^{4} \\ \color{orange} \rightarrow320000 \times ( \frac{21}{20} ) {}^{4} \\ \color{red} \rightarrow320000 \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \\ \pink{\rightarrow {32\cancel{0000} }\times \frac{21}{2 \cancel0} \times \frac{21}{2 \cancel0} \times \frac{21}{2 \cancel0} \times \frac{21}{2 \cancel0} }\\ = rs.388962 \\ \color{pink} \therefore \: Compound \: Interest = A- P \\ \color{aqua} \implies \: rs.388962 - Rs.320000 \\ \color{blue} \underline{= Rs.68962 }$

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More to known :)

• simple interest is generally used for loans of one year or less. for loans of more than one year, the interest paid on the money borrowed usually use compound interest.

• compound interest is interest calculated not only on the original principal, but also on any interest that has already been earned.

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