Question

find the amount and the compound interest on 3000 for 2 year at 10% per annum.​

Answer 1

Answer:

okkkkkkkkkkkkkkkkkkk bro

Answer 2

Given,

$\bf{Principal} = \rm 3000 \\ </p><p> \bf{}Time = \rm 2 \: \: yrs\\ </p><p> \bf{}Rate = \rm10\% \: \: \: per \: annum$

$\huge\text{Formula Used :- } \\ \\ \bull \: \: \tt Amount = { \tt P \bigg(1 + \frac{R}{100} \bigg)^{t} }\\ \\ \bull \: \: \tt Compund \: Interest = { \tt P \bigg(1 + \frac{R}{100} \bigg)^{t} - P}$

So,

$\rm{}Amount = 3000 { \bigg(1 + \frac{1\cancel0}{10\cancel0} \bigg)}^{2} \\ \\ =>3000 {\bigg(1 + \frac{ 1 }{10} \bigg)}^{2} \\ \\ =>3000 \times {\bigg( \frac{10 + 1}{10} \bigg)}^{2} \\ \\ =>3000 \times \frac{ {11}^{2} }{ {10}^{2} } \\ \\ =>30\cancel{00 }\times \frac{121}{1\cancel{00}} \\ =>30 \times 121 \\\implies \red{ 3630}$

And,

$\rm{}CI = A - P \\ \\ =>3630 - 3000 \\ => \red{630}$

Hence,

• Amount = Rs. 3630
• Interest = Rs. 630