Question

Find the amount and the compound interest on ₹4,000 in 2 years, if the rate of interest for first year is 10%and for the second year is 15%​

Answer 1

Step-by-step explanation:

first compound interest=4000 for 2years

1 year compound interest 4000/2

=2000

if I,

first year interest 10%

second year interest 15%

2000 rupes for rate interest 2000/10

one year rate interest 200

second year rate interest 2000/15

second year rate interest 133.34

Answer 2

Answer:

1st Year  

Principal, P=Rs.4000

Time, T=1 year

Rate of interest ,R=10% p.a.

∴simple Interest, SI= PTR/100

= Rs. (4000 X 1 X 10)/100

= Rs. 400  

∴Amount=P+SI=Rs.4400

2nd year

Principal = Amount of 1st year=Rs.4400

Rate of interest =15%

Time =1 year

∴ Interest = Rs.{(4400 x 15 x 1)/100}

= Rs.660  

∴ Amount =Rs.(4400+660)=Rs.5060

The interest of 2nd year is the required compound interest. So, C.I=Rs.1060 and the required amount is Rs.5060

Step-by-step explanation: