Question

the ratio of acid and water in 45 liters
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Answer 1

Let's add x litres of water

Now if the solution is 45% acid then it is 55% water.

Equating water in initial and final solution, When solution is 25% acid:

x+0.55(1125)=0.75(x+1125)  

x+618.75=0.75x+843.75  

0.25x=225

x=900  (to get 25% of acidic solution)

Answer 2

Answer:

Let's add x litres of water

Now if the solution is 45% acid then it is 55% water.

Equating water in initial and final solution, When solution is 25% acid:

x+0.55(1125)=0.75(x+1125)

x+618.75=0.75x+843.75

0.25x=225

x=900 (to get 25% of acidic solution)

Equating water in initial and final solution, When solution is 30% acid:

x+0.55(1125)=0.7(x+1125)

x+618.75=0.7x+787.5

0.3x=168.75

x=562.5 (to get 30% of acidic solution)

i.e 562.5<x<900