Question

find the Amount and the compound interest on


rs 10,0000 for
$1 \times \frac{1}{2}$

ch =comparing quantities ​

Answer 1

Correct Question :--- Find the Amount and compound interest on Rs. 10000 for 1(1/2) = 3/2 years at 10% per annum. ?

Concept used :--- Compound interest is calculated on the

principal amount and also on the accumulated

interest of previous periods, and can thus be

regarded as interest on interest.

→ But, Here we won’t use the Formula of

Compound Interest. we will use Simple Interest Formula Only.

→ Interest on First Year of Simple Interest

and Compound Interest are always equal.

→ Principal for Compound interst for next

consecutive years can be find by Adding

Principal and Past Year Interest..

______________________________

Solution :---

Given :--

→ Principal = Rs. 10, 0000

→ Rate = 10%

→ Time = 3/2 years = 1 year + 1/2 year.

→ SI of First Year = P * R * T /100

Putting values we get ,

→ SI = 100000 * 10 * 1 /100

→ SI = Rs.10000

So,, Amount After 1 year = P + SI

→ Amount = 100000 + 10000 = Rs. 110000

_____________________________

Now, we have to Find interest of Half year also ,

→ P now = Rs.110000

→ Rate = 10%

→ Time now = 1/2 year .

→ SI = 110000 * 10 * 1 / 100 * 2

→ SI = Rs.5500

______________________________

So, Total CI After (3/2) year we get = Rs. 10000 + Rs.5500 = Rs. 15500

→ Amount After (3/2) year will be = 100000 + 15500 = Rs. 1,15,500 (Ans)..

Answer 2

Answer:

Amount after 1.5 year is Rs 115500

Step-by-step explanation:

We Have :-

Principal = Rs 100000

Rate = 10%

Time = 3/2 = 1.5 years = 1 year + 6 months

To Find :-

Amount and Compound Interest

Formula Used :-

SI = ( P * R * T ) / 100

Solution :-

For First Year

SI = ( 100000 * 10 * 1 ) / 100

= Rs 10000

For Half year

SI = ( 110000 * 10 * 0.5 ) / 100

= Rs 5500

Amount after 1 year = Rs 100000 + Rs 10000

= Rs 110000

Amount after 1.5 year = Rs 110000 + 5500

= Rs 115500

Amount after 1.5 year is Rs 115500