Math, asked by priyanshipal1278, 6 months ago

find the amount and the compound interest on rupee 20000 for 3/2years at 10 %per annum . compounded half-yearly. would this intreste be more than the interst he would get if it was compounded annually​

Answers

Answered by 4radhika6
0

Answer:

Step-by-step explanation:

থযরযলযথমচতভণযথযমণথথতভতমণণঙৈ

Answered by ashauthiras
1

Answer:

Rs.4869

Step-by-step explanation:

Given,

Principal,P =Rs.18000,  Rate,R = 10%   and time period,n = 2.5 years.  

We know, Amount when interest is compounded annually = P(1+\frac{R}{100})^n

Amount after 2 years at 10% , A = 18000(1+\frac{10}{100})^2 = Rs.21780

This acts as the principal amount for the next half year.

SI on next 1/2 year at = \frac{21780\times\frac{1}{2}\times10}{100}= Rs. 1089

Therefore, Total amount to be paid after 2.5 years = Rs. (21780+1089) = Rs.22869

Now, Compound Interest after 2 years = A - P = Rs.(21780-18000) = Rs. 3780

Therefore, Compound Interest after 2.5 years, CI = Rs. 3780 + SI = Rs.4869

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