find the amount and the compound interest on rupees 20480 for 3 / 2 years at 25 / 2% per annum
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Answered by
9
Solutions :-
Given :
Principle = p = Rs 20480
Time = t = 3/2 years = 1.5 years
Rate = 25/2 % p.a. = 12.5 % p.a.
Find the Amount (A) :-
A = p (1 + r)^t
= 20480 (1 + 12.5%)^1.5
= 20480 (1 + 0.125)^1.5
= 20480 (1.125)^1.5
= 20480 × 1.1932426933
= 24437.61 (approx.)
Find the compound Interest (C.I) :-
C.I = A - p
= Rs (24437.61 - 20480)
= Rs 3957.61
Hence,
Amount = Rs 24437.61
Compound Interest = Rs 3957.61
Given :
Principle = p = Rs 20480
Time = t = 3/2 years = 1.5 years
Rate = 25/2 % p.a. = 12.5 % p.a.
Find the Amount (A) :-
A = p (1 + r)^t
= 20480 (1 + 12.5%)^1.5
= 20480 (1 + 0.125)^1.5
= 20480 (1.125)^1.5
= 20480 × 1.1932426933
= 24437.61 (approx.)
Find the compound Interest (C.I) :-
C.I = A - p
= Rs (24437.61 - 20480)
= Rs 3957.61
Hence,
Amount = Rs 24437.61
Compound Interest = Rs 3957.61
Answered by
3
Dear ,
Here is Your Answer ⏬
Given that ;-
• Principle = ₹20480
• Time = 3/2 years i.e. = 1.5 years.
• Rate = 25/2% i.e. 12.5%.
Now ,
Finding the Amount ;-
We know that ;-
• A = P ( 1 + R / 100 )n
Then ,
Now ,
Finding the Compound Interest ( CI ) ;-
We know that ;-
• CI = A - P
Then ,
Therefore ,
A = ₹ 24437.61
CI = ₹ 3957.61
- Regards
@ItsDmohit ( Brainly Warrior )
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