Question

Find the amount and the compound interest on rupees 24000 for 2 years at 10% per annum compounded yearly

Answer 1

AMOUNT =PRINCIPAL[1+(R/100)] power'n

$24000(1 + \frac{10}{100} ) ^{2}$
$24000( \frac{11}{10})^{2}$
$240 \times 121$
29040/-

C.I=P[(1+R/100)-1]
=24000[1+(10/100)-1]
=24000[(11/10)-1]
24000[1/10]
2400