Question

find the amount due and the compound interest on 30000 at 8% pa. compounded half yearly for 2 years​

Answer 1

Answer:

The Compound Interest is Rs. 4992.

Step-by-step explanation:

Given :

Sum of money = 30,000

Rate = 8%

Time = 2 years

To find :

Compound interest

Solution :

$\bigstar \: {\boxed{\sf{A= P\left( 1 + \frac{R}{100}\right)^{N}}}}$

$\sf{\implies} \: A= 30000\left( 1 + \dfrac{8}{100}\right)^{2} \\ \\ \sf{\implies} \: A= 30000\left( \dfrac{108}{100}\right)^{2} \\ \\ \sf{\implies} \: A= 3\cancel{00}\cancel{00}\times \dfrac{108}{1\cancel{00}} \times \dfrac{108}{1\cancel{00}} \\ \\ \sf{\implies} \: A = 3 \times 108 \times 108 \\ \\ \sf{\implies} \: A = 3 \times 11664 \\ \\ \sf{\implies} \: A = 34992$

Amount = 34,992

$\rule{300}{1.5}$

$\bigstar \: \boxed{\sf{CI = Amount - Principal}}$

$\sf{\implies} \:CI = 34992 - 30000 \\ \\ \sf{\implies} \:CI = 4992$

Compound Interest = Rs. 4992

$\therefore$ The Compound Interest is Rs. 4992.

Answer 2

Answer:

Compound Interest=4992

Step-by-step explanation:

$\huge\mathbb\orange{Solution:}$

$\huge\mathbb\pink{Given:-}$

☆ Principal (P) =30000

☆ Rate of Interest (r) =8%

☆ Time(n) =2 years.

$\huge\mathbb\orange{Formula\:applied}$

Compound Interest:-

$\implies CI={P(1+r)}^{n}-P$

$\implies CI={30000(1+8\%)}^{2}-30000$

$\implies CI={30000(1+0.08)}^{2}-30000$

$\implies CI={30000(1.08)}^{2}-30000$

$\implies CI=30000\times1.1664-30000$

$\implies CI=34992-30000$

$\implies CI=4992$

$\huge{\boxed{\mathtt{CI=4992}}}$

Hope it helps you ♡ ♡ ♡