Question

Find the amount for Rs. 4000 for 2 years at the rate of 8% per annum.​

Rs.4665.60

Rs.4865.60

Rs.3665.60

Rs.4635.60

which one is the answer?

Answer 1

Answer:

Rs.4865.60

Step-by-step explanation:

plz make me brainlist

Answer 2

Answer:

Given :-

• A sum of Rs 4000 for 2 years at the rate of 8% per annum.

To Find :-

• What is the amount.

Formula Used :-

$\clubsuit$ Amount Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{A =\: P\bigg(1 + \dfrac{r}{100}\bigg)^n}}}\: \: \: \bigstar$

where,

• A = Amount
• P = Principal
• r = Rate of Interest
• n = Time Period

Solution :-

Given :

• Principal (P) = Rs 4000
• Rate of Interest (r) = 8% per annum
• Time Period (n) = 2 years

According to the question by using the formula we get,

$\implies \bf A =\: P\bigg(1 + \dfrac{r}{100}\bigg)^n$

$\implies \sf A =\: 4000\bigg(1 + \dfrac{8}{100}\bigg)^2$

$\implies \sf A =\: 4000\bigg(\dfrac{100 \times 1 + 8}{100}\bigg)^2$

$\implies \sf A =\: 4000\bigg(\dfrac{100 + 8}{100}\bigg)^2$

$\implies \sf A =\: 4000\bigg(\dfrac{108}{100}\bigg)^2$

$\implies \sf A =\: 4000\bigg(\dfrac{108}{100} \times \dfrac{108}{100}\bigg)$

$\implies \sf A =\: 4000\bigg(\dfrac{108 \times 108}{100 \times 100}\bigg)$

$\implies \sf A =\: 4000\bigg(\dfrac{11664}{10000}\bigg)$

$\implies \sf A =\: 4000 \times \dfrac{11664}{10000}$

$\implies \sf A =\: \dfrac{4000 \times 11664}{10000}$

$\implies \sf A =\: \dfrac{46656000}{10000}$

$\implies \sf\bold{\red{A =\: Rs\: 4665.60}}$

$\sf\bold{\purple{\underline{\therefore\: The\: amount\: is\: Rs\: 4665.60\: .}}}$

Hence, the correct options is option no (A) 4665.60 .

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