Math, asked by prathikprakyathi, 1 month ago

Find the amount for the SECOND YEAR on ₹ 6000 in 2 yrs if the rate of interest is 5 % for the first year and 4 % for the second year

Answers

Answered by 5346720arnavtyagi
0

Answer:

1st year calculation

Calculate:

Total P+I (A)

Where: A = P(1 + r/n)^(nt)

Principal (P): $ 6,000.00

Rate (R): % annual 5

Compound (n): Compounding Annually (1/Yr)

Time (t in years): 1

Answer:

A = $ 6,300.00

A = P + I where

P (principal) = $ 6,000.00

I (interest) = $ 300.00

2nd year calculation

Calculate:

Total P+I (A)

Where: A = P(1 + r/n)^(nt)

Principal (P): $ 6,300.00

Rate (R): % annual 5

Compound (n): Compounding Annually (1/Yr)

Time (t in years): 1

Answer:

A = $ 6,615.00

A = P + I where

P (principal) = $ 6,300.00

I (interest) = $ 315.00

3rd year calculation

Calculate:

Total P+I (A)

Where: A = P(1 + r/n)^(nt)

Principal (P): $ 6,615.00

Rate (R): % annual 5

Compound (n): Compounding Annually (1/Yr)

Time (t in years): 1

Answer:

A = $ 6,945.75

A = P + I where1st year calculation

Calculate:

Total P+I (A)

Where: A = P(1 + r/n)^(nt)

Principal (P): $ 6,000.00

Rate (R): % annual 5

Compound (n): Compounding Annually (1/Yr)

Time (t in years): 1

Answer:

A = $ 6,300.00

A = P + I where

P (principal) = $ 6,000.00

I (interest) = $ 300.00

2nd year calculation

Calculate:

Total P+I (A)

Where: A = P(1 + r/n)^(nt)

Principal (P): $ 6,300.00

Rate (R): % annual 5

Compound (n): Compounding Annually (1/Yr)

Time (t in years): 1

Answer:

A = $ 6,615.00

A = P + I where

P (principal) = $ 6,300.00

I (interest) = $ 315.00

3rd year calculation

Calculate:

Total P+I (A)

Where: A = P(1 + r/n)^(nt)

Principal (P): $ 6,615.00

Rate (R): % annual 5

Compound (n): Compounding Annually (1/Yr)

Time (t in years): 1

Answer:

A = $ 6,945.75

A = P + I where

Step-by-step explanation:

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