Question

find the amount interest when it is compounded annually.. I Will also try .​

Answer 1

GIVEN :-

• Principal ( P ) = Rs. 625.
• Rate ( R ) = 4 %.
• Time ( n ) = 2 years.

TO FIND :-

• The Amount ( A ).
• The compound Interest ( CI ).

SOLUTION :-

As we know that,

⇒ Amount = P(1 + R/100)ⁿ

⇒ Amount = 625(1 + 4/100)²

⇒ Amount = 625{(100 + 4)/100}²

⇒ Amount = 625(104/100)²

⇒ Amount = 625 × 10816/10000

⇒ Amount = 6760000/10000

⇒ Amount = Rs. 676

Now,

⇒ Compound Interest = Amount - Principal

⇒ Compound Interest = Rs. 676 - Rs. 625

⇒ Compound Interest = Rs. 51

Hence the required Amount is Rs. 676 and the required compound interest is Rs. 51.

Answer 2

Answer:

$\huge \bf \: solution$

$\sf \: principal(p) = 625$

$\sf rate \:(r) = 4\%$

$\sf \: time \: = 2 \: years$

Aply Formula

$\bf \:amount \: = P ( { 1 + \frac{r}{100} })^{n}$

$\sf \: amount \: = 625 ({1 + \frac{4}{100}) }^{2}$

$\sf \: amount \: = 625( { 1 +\frac{100+4}{100}) }^{2}$

$\sf \: amount \: = 625+ { \frac{104}{100} }^{2}$

$\sf \: amount \: = \frac{10816}{10000}$

$\sf \: \frac{6760000}{10000}$

$\huge \fbox {amount \: = 676}$

Now,

Compound interest = Amount - Principal

$\sf \: \: compound \: intrest = \: 676 - 625$

$\huge \bf \: ci \: = 51$