find the amount of heat required to change 10 gram of ice at -5℃ to water at 20℃. please answer it
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Q = mc∆T
Q= Total heat required to change the temperature by ∆T of m gram of the subtance.
c = Heat capacity of that substance.
Here in this case Heat capacity of water is
= 4.18J/(g °C)
Phase 1: from (-5°C)ice to 0°C ice
Q= 10 x 4.18 x 5
= 209J
Phase 2: 0°C ice to 0°C water
Q = gL
Here L = Latent heat of water per gram. =
334 joules per gram,
Q= 10x334 = 3340 J
Phase 3 : from 0°C water to 20°C water.
Q3= 10 x 4.18 x 20 = 836 J
Total Q= Q1 +Q2+ Q3
= 209+3340+836
= 4385 J
Q= Total heat required to change the temperature by ∆T of m gram of the subtance.
c = Heat capacity of that substance.
Here in this case Heat capacity of water is
= 4.18J/(g °C)
Phase 1: from (-5°C)ice to 0°C ice
Q= 10 x 4.18 x 5
= 209J
Phase 2: 0°C ice to 0°C water
Q = gL
Here L = Latent heat of water per gram. =
334 joules per gram,
Q= 10x334 = 3340 J
Phase 3 : from 0°C water to 20°C water.
Q3= 10 x 4.18 x 20 = 836 J
Total Q= Q1 +Q2+ Q3
= 209+3340+836
= 4385 J
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