the numerator of a fraction is 3 less than the denominator if both the numerator and denominator is increased by 2 the new fraction becomes 6 upon 7 find the original fraction
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value of x and y are 16 and 19 so the fraction will become x/y=16/19
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shreshth71:
kashish the answer is 16upon 19
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Hiii....☺
Here is your solution......
♦ Let the denominator of the fraction be " x "
=> Numerator = (x-3)
According to given condition we have,
=> x - 3 + 2/ x + 2 = 6/7
=> x - 1/ x + 2 = 6/7
=> 7( x - 1 ) = 6 ( x + 2)
=> 7x - 7 = 6x + 12
=> 7x - 6x = 12+ 7
=> x = 19
♦ Denominator of the fraction = x = 19
♦ Numerator of the fraction = x - 3 = 19 - 3 = 16
Hence, original fraction = 16/19.
Thanks...☺
Here is your solution......
♦ Let the denominator of the fraction be " x "
=> Numerator = (x-3)
According to given condition we have,
=> x - 3 + 2/ x + 2 = 6/7
=> x - 1/ x + 2 = 6/7
=> 7( x - 1 ) = 6 ( x + 2)
=> 7x - 7 = 6x + 12
=> 7x - 6x = 12+ 7
=> x = 19
♦ Denominator of the fraction = x = 19
♦ Numerator of the fraction = x - 3 = 19 - 3 = 16
Hence, original fraction = 16/19.
Thanks...☺
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