Question

Find the amount of heat required to change when 20 grams of h2o from 10 degrees to 20degrees celcius.

Answer 1

Answer:he easy way is to use calories instead of joule when calculating.

Also use 1 gram instead of 20 gram.

Specific heat capacity for ice = 0.5 cal / g / deg

Heat of fusion for water = 80 cal / g

Specific heat capacity for water = 1 cal / g / deg

For 1 gram:

-10 ice -> 0 ice : 1* 0.5 * 10 = 5 cal

0 deg. ice -> 0 deg. water = 1* 80 cal

0 deg water to 20 deg water: 1*1.0*20 = 20 cal

= 105 cal.

Total for 1 gram : 105 cal, for 20 grams = 2100 cal

in joule, multiply with 4.2 = 8820 Joule