Question

find the amount of water displaced by a solid spherical ball of diameter 28cm.​

Answer 1

$\huge \underline{ \mathbb{SOLUTION:-}}$

Given:-

• Diameter of the solid spherical ball = 28cm.

Need to find:-

• Amount of water displaced by a solid spherical.

Step by step explanation:

Diameter of the spherical ball = 28cm.

Therefore,

Radius of spherical ball = 28/2 = 14cm.

Amount of water displaced = Volume of spherical ball

$\large \implies{ \frac{4}{3} πr ^{3} }$

$\large \implies{ \frac{4}{3} \times \frac{22}{7} \times 14 \times 14 \times 14}$

$\large \implies{ \frac{88 \times 28 \times 14}{3} }$

$\large \implies{ \frac{2464 \times 14}{3}}$

$\large \implies{ \frac{34496}{3}}$

$\large \implies{ \bold{11498.66 {cm}^{3} }}$

Hence,the amount of water displaced by a solid spherical ball of diameter 28cm is 11498.66cm³.