Find the amount P = Rs 10000, R = 5% p.a and T = 5 years
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Answer:
Solution: Principal for the first year = Rs. 10000
Interest for the first year =
Rs \dfrac{10000 \times 5 \times 1}{100} = Rs. 500
[We are using the formula
S.I.=\dfrac{P \times R \times T}{100} ]
\therefore amount at the end of first year = Rs 10000 + Rs. 500 = Rs. 10500
Interest for the second year =
\dfrac{10500 \times 5 \times 1}{100} = Rs. 525
Principal of the second year was Rs. 10500 and so amount at the end of the second year = Rs. 10500 + Rs. 525 = Rs. 11025
So, Compound interest= Rs. (11025 – 10000) = Rs. 1025
Note: The C.I. can also be found by adding the interest for each year.
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